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25 January, 01:39

A 250g sample of water with an initial temperature of 98.8oC loses 1794 cal of heat. What is the final temperature of the water?

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  1. 25 January, 02:54
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    91.62 C

    Explanation:

    Q = (m) (Csh) (T2 - T1)

    T2 = T1 + (Q) / (m) (Csh)

    T2 = 98.8 C + ( - 7500 J) / (250 g) (4.186 J/g - C)

    T2 = 91.6 C
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