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2 November, 00:12

What pressure in kPa is exerted by 2.150 mol of Co, at 57.00 °C in 0.7500 L?!

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  1. 2 November, 02:41
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    This is an ideal gas law question. Use the equation PV = nRT.

    P (0.75) = (2.150) (0.08206) (273+57)

    P = 77.63atm

    The answer needs to be in kPa and theres 101.325kpa per 1atm, so

    77.63*101.325 = 7865.73 kPa

    If youre supposed to have 3 significant figures, then 7870kPa
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