For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that will be extracted after seven (7) extractions using a certain solvent D if 0.90 mL of a certain organic solvent D was used for each extraction. Given Ksolvent D/water = 1.8.

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K) (Vaq/Vo) ], where

x = mass extracted

m = total mass of solute

K = distribution coefficient

Vo = volume of organic layer

Vaq = volume of aqueous layer

dа ta:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K) (Vaq/Vo) = 1 + (1/1.8) (1.00/0.90) = 1 + 0.62 = 1.62

x = m/1.62 = 0.618m

So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

Let r = the amount remaining after n extractions. Then

r = m (0.382) ^n.

If n = 7,

r = 75 (0.382) ^7 = 75 * 0.001 18 = 0.088 mg

m = 75 - 0.088 = 75 mg

After seven extractions, 75 mg (99.999 %) of the solute will be extracted.