What is the molarity of a solution containing 45.78gMgCl2 dissolved in 3.00L of solution?

The formula is M (molarity) = mol / liters

molarity = ?

mass = 45.78g of MgCl2

Volume = 3.00L

1 / Convert grams to mol by using the formula: mol = mass / Molar mass

a / Molar mass of MgCl2:

Mg = 1 x 24.30 = 24.30 g/mol

Cl = 2 x 35.45 = 70.9 g/mol

Add them together:

24.30 g/mol + 70.9 g/mol = 95.2 g/mol

b / mol = mass / Molar mass

mol = 45.78 g / 95.2 g/mol

mol = 0.4808

==> 0.4808 mol of MgCl2

2 / M = ?

mol = 0.4808 mol of MgCl2

Volume = 3.00L

M = mol / liters

M = 0.4808 mol / 3.00 L

M = 0.16 mol/L