From the following balanced equation,

4NH3 (g) + 5O2 (g) ⟶4NO (g) + 6H2O (g)

how many grams of H2O can be formed from 6.12g NH3?

9.72 grams.

Explanation:

From the equation, 4 moles of NH₃ produce 6 moles of water.

Therefore the reaction to product ratio of NH₃ to H₂O is 4:6

and 2:3 into its simplest form.

The number of moles of NH₃ in 6.12 g is:

Number of moles=mass / RMM

=6.12 g/17 G/mol

=0.36 moles.

Therefore the number of moles of H₂O produced is calculated as follows.

(0.36 Moles*3) 2 = 0.54 moles

Mass = Number of moles * RMM

=0.54 moles*18g/mol

=9.72 grams.