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19 June, 20:59

Warming a gas at constant volume and a pressure of 1.50 atm from 27 degrees Celsius to 127 degrees Celsius gives a final pressure of

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  1. 19 June, 22:39
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    Final pressure of gas = 2 atm

    Explanation:

    Given dа ta:

    Initial pressure of gas = 1.50 atm

    Initial temperature = 27°C

    Final temperature = 127°C

    Final pressure of gas = ?

    Solution:

    Initial temperature = 27°C (27+273 = 300 K)

    Final temperature = 127°C (127+273 = 400 K)

    According to Gay-Lussac Law,

    The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

    Mathematical relationship:

    P₁/T₁ = P₂/T₂

    Now we will put the values in formula:

    1.50 atm / 300 K = P₂/400 K

    P₂ = 1.50 atm * 400 K / 300 K

    P₂ = 600 atm. K / 300 K

    P₂ = 2 atm
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