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4 June, 03:41

Use the ksp values in the table to calculate the molar solubility of fe (oh) 2 in pure water

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  1. 4 June, 04:35
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    The solubility equilibrium for Fe (OH) 2 is:

    Fe (OH) 2 (aq) ↔ Fe²⁺ (aq) + 2OH⁻ (aq)

    Ksp (Fe (OH) 2) = [Fe²⁺][OH⁻]²

    If 's' is the molar solubility of Fe (OH) 2 then:

    Ksp = (s) (2s) ² = 4s³

    the solubility constant Ksp for Fe (OH) 2 can be obtained from any online database = 4.87*10⁻¹⁷

    4.87*10⁻¹⁷ = 4s³

    s³ = 1.218*10⁻¹⁷

    s = ∛1.218*10⁻¹⁷ = 2.33*10⁻⁶ M

    Molar solubility of Fe (OH) 2 = 2.33*10⁻⁶ M
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