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31 March, 12:05

In a lab, 2.20 L of gas is collected over water at a temperature of 30 degrees C and a total pressure of 735.43 mmHg. Find the volume that the dry nitrogen of gas would occupy at STP.

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  1. 31 March, 14:24
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    Volume of nitrogen at STP = 1.92 L

    Explanation:

    Given dа ta:

    Initial volume of gas = 2.20 L

    Initial temperature = 30°C (30+273 = 303 k)

    Initial pressure = 735.43 mmHg (735.43/760 = 0.97 atm)

    Final volume = ?

    Final pressure = 1 atm

    Final temperature = 273 K

    Solution:

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₂ = P₁V₁ T₂ / T₁ P₂

    V₂ = 0.97 atm * 2.20 L * 273 K / 303 K * 1 atm

    V₂ = 582.58 atm. L. K / 303 K. atm

    V₂ = 1.92 L
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