10.8 moles of SO3 would be how many grams?

Answer: 864 grams

Explanation:

Given that,

Amount of moles of SO3 (n) = 10.8

Mass of SO3 in grams (m) = ?

For molar mass of SO3, use the molar masses:

Sulphur, S = 32g;

Oxygen, O = 16g

SO3 = 32g + (16g x 3)

= 32g + 48g

= 80g/mol

Since, amount of moles = mass in grams / molar mass

10.8 mole = m / 80g/mol

m = 10.8 mole x 80g/mol

m = 864g

Thus, 10.8 moles of SO3 would be 864 grams