What volume (mL) of 7.48x10 - 2 M phosphoric acid can be completely reacted with 115 mL of. 244 M sodium

hydroxide? Hint: balance equation

Answer:125ml - volume of phosphoic acid

Explanation:

The equation of the reaction is

H3PO4 + 3 NaOH - --> Na3PO4 + 3H2O

Such that I mole of H3PO4 reacts with 3 moles of NaOH to produce the products above.

Given that

M1 = Molarity of phosphoric acid = 7.48x10^-2 M

n1 = number of moles of phosphoric acid = 1

V1=? ml

M2 = Molarity of Sodium hydroxide = 0.244 M

V2 = volume of sodium hydroxide = 115ml

n2=number of moles of sodium hydroxide = 3

Using the Dilution equation formulae,

M1V1/n1 = M2V2/n2

7.48X10-2 x V1 / 1 = 0.244M x 115ml/3

V1=0.244Mx115mlx1/0.0748M X 3

V1 = 28.06/0.2244 = 125.04ml

V1=125.04ml rounded up to 125ml