What is the molarity of a saline solution that contains 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 mL of solution?

The molarity of a saline solution that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is 0.15 M

calculation

Molarity = moles / volume in liters

volume in liters = 100.0 ml / 1000 = 0.1 L

moles = mass: molar mass

= 0.900 g : 58.44 g/mol = 0.015 moles

molarity is therefore = 0.015 moles / 0.1 L = 0.15 M