Ask Question
Today, 00:38

What is the molarity of 500 ml of a solution containing 85.0g AgNO3? A) 0.5 M B) 1.0 M C) 2.0 M D) 5.0 M

+1
Answers (1)
  1. Today, 01:07
    0
    Consider the equation for calculating molarity: (no. of mole of solute) : (volume of solution)

    First, let's find the no. of mole of solute in AgNO3. As (no. of mole) = mass / molar mass

    no. of mole of 85.0g of AgNO3 = 85.0 / (107.9+14.0+16.0x3)

    =0.5mol

    Since the volume of the solution has to be in dm3, just divide the volume in cm3 by 1000 to get the volume in dm3.

    Volume of solution = 500/1000

    = 0.5 dm3

    Therefore, the molarity is

    0.5/0.5

    =1.0M

    The answer should be B.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the molarity of 500 ml of a solution containing 85.0g AgNO3? A) 0.5 M B) 1.0 M C) 2.0 M D) 5.0 M ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers