2H2S + 3O2 2SO2 + 2H2O Which option gives the correct mole ratios? H2S:SO2 = 2:2 and O2:H2O = 3:2 H2S:SO2 = 2:3 and O2:H2O = 3:2 H2S:SO2 = 4:4 and O2:H2O = 5:4 H2S:SO2 = 4:6 and O2:H2O = 4:4

Question

Chemistry

Dillon Harris

25 August, 06:23

2H2S + 3O2 2SO2 + 2H2O Which option gives the correct mole ratios? H2S:SO2 = 2:2 and O2:H2O = 3:2 H2S:SO2 = 2:3 and O2:H2O = 3:2 H2S:SO2 = 4:4 and O2:H2O = 5:4 H2S:SO2 = 4:6 and O2:H2O = 4:4

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Answers (1)

Know the Answer?

Eden Hammond · Answer 1

Correct Answer: Option (A)

H₂S : SO₂ = 2:2 and,

O₂: H₂O = 3:2

Explanation:

The mole ratio is the ratio of coefficients of the compounds involved in the reaction. Reactants, as on the left hand side of the chemical reaction which reach to form new products.

In the given reaction,

2H₂S + 3O₂ ⇒ 2SO₂ + 2H₂O

The reactants are : H₂S (hydrogen sulphide) & O₂ (oxygen)

The products are : SO₂ (sulphur dioxide) & H₂O (water)

2 moles of hydrogen sulphide react with 3 moles of oxygen 2 moles of sulphur dioxide & 2 moles of water are produced

Therefore correct option is

H₂S : SO₂ = 2:2 and,

O₂: H₂O = 3:2