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6 October, 16:32

Practice Problem #1: __TiO2 + __Cl2 + __C __TiCl4 + __CO2 + __CO

How many mol chlorine will react with 4.55 mol carbon?

What mass titanium (IV) oxide will react with 4.55 mol carbon?

How many molecules titanium (IV) chloride can be made from 115 g titanium (IV) oxide?

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Answers (1)
  1. 6 October, 18:03
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    1)

    Given dа ta:

    Moles of Cl₂ react = ?

    Moles of carbon = 4.55 mol

    Solution:

    Chemical equation:

    2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

    Now we will compare the moles of Cl₂ with C.

    C : Cl₂

    3 : 4

    4.55 : 4/3*4.55 = 6.1 mol

    6.1 moles of chlorine will react with 4.55 moles of C.

    2)

    Given dа ta:

    Mass of TiO₂ react = ?

    Moles of carbon = 4.55 mol

    Solution:

    Chemical equation:

    2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

    Now we will compare the moles of Cl₂ with C.

    C : TiO₂

    3 : 2

    4.55 : 2/3*4.55 = 3 mol

    Mass of TiO₂:

    Mass = number of moles * molar mass

    Mass = 3 mol * 79.87 g/mol

    Mass = 239.61 g

    3)

    Given dа ta:

    Molecules of TiCl₄ formed = ?

    Moles of TiO₂ react = 115 g

    Solution:

    Chemical equation:

    2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

    Number of moles of TiO₂:

    Number of moles = mass / molar mass

    Number of moles = 115 g / 79.87 g/mol

    Number of moles = 1.44 mol

    Now we will compare the moles of Cl₂ with C.

    TiO₂ : TiCl₄

    2 : 2

    1.44 : 1.44

    Molecules of TiCl₄:

    1 mole = 6.022 * 10²³ molecules

    1.44 * 6.022 * 10²³ molecules

    8.672 * 10²³ molecules
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