A canister of 2.00 moles of helium has a volume of 30.0 L and is at a temperature of 293 Kelvin. what is the pressure of this gas?

1. 19.5 kPa

2. 101.3 kPa

3. 162 kPa

4. 211 kPa

P = 162 KPa

Explanation:

Given dа ta:

Number of moles = 2 mol

Volume of gas = 30.0 L

Temperature of gas = 293 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P = Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm. L / mol. K

T = temperature in kelvin

P = nRT/V

P = 2 mol * 0.0821 atm. L / mol. K * 293 K / 30.0 L

P = 48.11 atm. L / 30.0 L

P = 1.6 atm

atm to kelvin:

1.6*101 = 162 KPa