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28 April, 06:02

35g of HF was prepared by reacting 112g of CaF2 with an excess of H2SO4 calculate the percentage yield

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  1. 28 April, 09:04
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    Answer: 61%

    The reaction equation should be

    CaF2 + H2SO4 → 2HF + CaSO4

    For every 1 molecule CaF2 used, there will be 2 molecules of HF formed. The molecular mass of CaF2 is 78/mol while the molecular mass of HF is 20g/mol. If the yield is 100%, the amount of HF formed by 112g CaF2 would be: 112g / (78g/mol) * 2 * (20g/mol) = 57.43g

    The percentage yield of the reaction would be: 35g/57.43g = 60.94%
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