When 1.57 mol o2 reacts with h2 to form h2o, how many moles of h2 are consumed in the process?

Here we have to get the moles of hydrogen (H₂) consumed to form water (H₂O) from 1.57 moles of oxygen (O₂)

In this process 3.14 moles of H₂ will be consumed.

The balanced reaction between oxygen (O₂) and hydrogen (H₂); both of which are in gaseous state to form water, which is liquid in nature can be written as-

2H₂ (g) + O₂ (g) = 2H₂O (l).

Thus form the equation we can see that 1 mole of oxygen reacts with 2 moles of hydrogen to form 2 moles of water.

So, 1.57 moles of oxygen will consume (1.57*2) = 3.14 moles of hydrogen to form water.

The reaction showing the synthesis of water from its elements:

2H₂ + O₂ - -> 2H₂O

One mole of oxygen combines with 2 moles of hydrogen to form 1 mole of H₂O

If 1 mole O₂ consumes 2 moles H₂

then 1.57 moles of O₂ consumes = 1.57 x 2 moles of H₂

= 3.14 moles of H₂

Therefore, 3.14 moles of H₂ are consumed in the process.