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17 May, 00:54

A 2.026g sample of a hydrate of sodium carbonate (Na2CO3) is heated to remove water. After heating, the mass of the sample is 0.750 g. Calculate the percentage by mass of water in the sample.

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  1. 17 May, 02:53
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    62.98 % of the sample of hydrate is water

    Explanation:

    Step 1: Data given

    Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams

    After heating, the mass of the sample is 0.750 g

    Molar mass H2O = 18.02 g/mol

    Step 2: Calculate mass of water

    Mass water = mass of hydrate - mass of sample after heating

    Mass water = 2.026 grams - 0.750 grams

    Mass water = 1.276 grams

    Step 3: Calculate mass % percent of water

    Mass % of water = (mass of water / total mass hydrate) * 100 %

    Mass % of water = (1.276 grams / 2.026 grams) * 100 %

    Mass % of water = 62.98 %

    62.98 % of the sample of hydrate is water
  2. 17 May, 04:30
    0
    percentage mass of water = 62.98%

    Explanation:

    The reaction is a decomposition reaction whereby hydrate of sodium carbonate was heated to remove water. The actual weight of the hydrated compound is 2.026 grams. After heating, the mass of the sample was now 0.750 grams. The percentage of the water sample can be calculated as follows:

    total mass of hydrated sample = 2.026 grams

    mass of sample after heating = 0.750 grams

    mass of water removed = 2.026 - 0.750 = 1.276 grams

    percentage mass of water = mass of water/mass of hydrated compound * 100

    percentage mass of water = 1.276/2.026 * 100

    percentage mass of water = 127.6/2.026

    percentage mass of water = 62.9812

    percentage mass of water = 62.98%
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