The specific heat of water is 4.18 joules per gram Celsius. How much he does 225.0 g of water release when it cools from 85.5°C to 50.0°C

Answer: 33387.75J

Explanation:

The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = ?

Mass of water = 225.0g

C = 4.18 joules per gram Celsius (4.18J/g°C)

Φ = (Final temperature - Initial temperature)

= 85.5°C - 50°C = 35.5°C

Then, Q = MCΦ

Q = 225.0g x 4.18J/g°C x 35.5°C

Q = 33387.75J

Thus, 33387.75 joules of heat is released during cooling.