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Yesterday, 22:29

It requires 0.0780L of a 0.12 M HCl solution to completely neutralize 0.0280L of an unknown LiOH solution. What is the concentration of the unknown LiOH solution?

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  1. Yesterday, 23:42
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    C₂ = 0.334 M

    Explanation:

    Given dа ta:

    Volume of HCl = 0.0780 L

    Concentration of HCl = 0.12 M

    Volume of LiOH = 0.0280 L

    Concentration of LiOH = ?

    Solution:

    Formula:

    C₁V₁ = C₂V₂

    C₁ = Concentration of HCl

    V₁ = Volume of HCl

    C₂ = Concentration of LiOH

    V₂ = Volume of LiOH

    Now we will put the values in formula.

    C₁V₁ = C₂V₂

    0.12 M * 0.0780 L = C₂ * 0.0280 L

    0.00936 M. L = C₂ * 0.0280 L

    C₂ = 0.00936 M. L/0.0280 L

    C₂ = 0.334 M
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