Ask Question
13 January, 11:34

Read the given equation. Na2O2 + CO2 → Na2CO3 + O2 What volume of O2 gas is produced from 2.80 liters of CO2 at STP?

+3
Answers (1)
  1. 13 January, 12:58
    0
    1.40 L.

    Explanation:

    It is a stichiometric problem. Firstly, we should wright the reaction as a balanced equation:

    Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

    It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂. Then we should convert the volume of CO₂ (2.80 L) to moles via using the gas law of ideal gas: PV = nRT, n = PV / RT,

    Where, P is the pressure of the gas in atm (P at STP = 1.0 atm).

    V is the volume of the gas in L (V = 2.80 L).

    R is the general gas constant (R = 0.082 L. atm/mol. K).

    T is the temperature in K (T at STP = 0.0 °C + 273 = 273 K).

    ∴ n of CO₂ = PV / RT = (1.0 atm) (2.80 L) / (0.082 L. atm/mol. K) (273 K) = 2.80 / 22.386 = 0.125 mole.

    From the stichiometry:

    1.0 mole of CO₂ will produce → 0.50 mole of O₂

    0.125 mole of CO₂ will produce →? mole of O₂

    The number of moles of O₂ produced = (0.125 mole of CO₂) (0.50 mole of O₂) / (1.0 mole of CO₂) = 0.06254 mole. Finally, we can convert the number of moles of O₂ produced to volume using the mentioned gas law of ideal gas: V = nRT/P. V of O₂ produced = nRT / P = (0.06254 mole) (0.082 L. atm/mol. K) (273.0 K) / (1.0 atm) = 1.40 L.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Read the given equation. Na2O2 + CO2 → Na2CO3 + O2 What volume of O2 gas is produced from 2.80 liters of CO2 at STP? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers