In a 71.4 g sample of nahco 3 3 , how many grams of sodium are present?

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the molecular mass of NaHCO₃.

1 Na = 1 * 22.99 u = 22.99 u

1 H = 1 * 1.008 u = 1.008 u

1 C = 1 * 12.01 u = 12.01 u

3 O = 3 * 16.00 u = 48.00 u

TOTAL = 84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ * (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na