What is the new volume of a gas at standard pressure (760 mm Hg) if originally 2.30 L of the gas had a pressure of 725.0 mmHg?

2.19L

Explanation:

Information from the question include:

V1 (initial volume) = 2.3L

P1 (initial pressure) = 725mmHg

P2 (final pressure) = 760mmHg

V2 (final volume) = ?

With the Boyle's law equation P1V1 = P2V2, the final volume can easily be obtain as follow:

P1V1 = P2V2

725 x 2.3 = 760 x V2

Divide both side by 760

V2 = (725 x 2.3) / 760

V2 = 2.19L

Therefore, the new volume of the gas at standard pressure is 2.19L