You are holding a container of 28.7L of dinitrogen tetroxide. How many grams of gas are inside? Step by step.

=71.76 grams

Explanation:

At Room temperature and pressure, 1 mole of an ideal gas occupies a volume of 24 liters.

Therefore, the number of moles occupied by 28.7 L is:

(28.7*1) / 24=1.196 moles.

Mass=Number of moles * RMM

RMM of N₂O₂ is 60

mass=1.196 moles * 60 grams/mol

=71.76 grams