9. Let's say, you need to make 2.00 L of 0.05 M copper (II) nitrate solution. How many grams of

copper (II) nitrate will you require?

18.76 g of copper II nitrate

Explanation:

Now recall that we must use the formula;

n = CV

Where;

n = number of moles of copper II nitrate solid

C = concentration of copper II nitrate solution

V = volume of copper II nitrate solution

Note that;

n = m/M

Where;

m = mass of solid copper II nitrate

M = molar mass of copper II nitrate

Thus;

m/M = CV

C = 0.05 M

V = 2.00 L

M = 187.56 g/mol

m = the unknown

Substituting values;

m / 187.56 g/mol = 0.05 M * 2.00 L

m = 0.05 M * 2.00 L * 187.56 g/mol

m = 18.76 g of copper II nitrate

Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.