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29 January, 14:20

A reaction is expected to produce 28.3 moles of hydrogen gas. If the hydrogen is collected at 297 K and 1.08 atm, what is the volume?

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Answers (2)
  1. 29 January, 16:01
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    The answer is b. 639 L H2
  2. 29 January, 17:50
    0
    Volume = nRT/P

    n = number of particles (moles)

    R = universal gas constant (0.0821)

    T = temperature of gas (Kelvin)

    P = pressure (atm)

    The equation can be set up as (28.3moles) (297K) (0.0821) / 1.08atm, which equals 639 L of hydrogen gas.
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