if the volume of a gas at 200.0 kPa is 25.5 L. what is the new volume of the gas at 11.2 atm of pressure?

Answer: 2.22 litres

Explanation:

Given that,

Original pressure of gas (P1) = 200.0 kPa

[Since final pressure is given in atmosphere, Convert 200.0 kPa to atmosphere

If 101.325 kPa = 1 atm

200.0 kPa = 200.0/101.325

= 1.9738 atm]

Original volume of oxygen O2 (V1) = 25.5L

New pressure of gas (P2) = 11.2 atm

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P2V2

0.9738 atm x 25.5L = 11.2 atm x V2

24.8319 atm•L = 11.2 atm•V2

Divide both sides by 11.2 atm to get V2

24.8319 atm•L/11.2 atm = 11.2 atm•V2/11.2 atm

2.217 L = V2

[Round 2.217L to the nearest hundredth as 2.22L]

Thus, the new volume of the gas at 11.2 atm of pressure is 2.22 litres