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9 January, 16:39

Which is the correct equilibrium constant expression for the following reaction? Fe2O3 (s) + 3H2 (g) - -> 2Fe (s) + 3H2O (g) Kc = [Fe2O3] [H2]3/[Fe]2[H2O] Kc = [Fe]2[H2O]3/[Fe2O3] [H2]3 Kc = [H2]/[H2O] Kc = [H2O]3/[H2]3 Kc = [Fe] [H2O]/[Fe2O3] [H2]

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  1. 9 January, 20:04
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    The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

    Explanation:

    Step 1: Data given

    For the reaction aA + bB ⇆ cC + dD

    the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a

    Step 2: The balanced equation

    Fe2O3 (s) + 3H2 (g) - -> 2Fe (s) + 3H2O (g)

    Step 3: Calculate the equilibrium constant Kc

    Kc = [C]^c * [D]^d/[B]^b*[A]^a

    ⇒with [C] = [Fe]

    ⇒ with c = 2

    ⇒with [D] = [H2O]

    ⇒with d = 3

    ⇒with [A] = [Fe2O3]

    ⇒with a = 1

    ⇒with [B] = [H2]

    ⇒with b = 3

    Kc = [C]^c * [D]^d/[B]^b*[A]^a

    Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

    The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³
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