Determine the volume occupied by 2.5 mol of a gas at 18 °C if the pressure is 81.8 kPa?

74 litre

Explanation:

using ideal gas eqation PV=nRT

here P (pressure) = 81.8 kPa = 81.8*10^3 Pa

moles=2.5

temperature=273.15+18=291.15K

Gas constant R=8.314m^3-Pa/K-mol

now, V=nRT/P = 8.314*2.5*291.5/81.8*10^3 ≈74litre

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