The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively. If the percentage yield of Cl2 is 72%, what is its actual yield?

The actual yield is 43 g Cl₂.

The limiting reactant was MnO₂ because it gave the smaller mass of Cl₂.

∴ The theoretical yield is 60.25 g Cl₂.

% yield = actual yield/theoretical yield * 100 %

Actual yield = theoretical yield * (% yield/100 %) = 60.25 g * (72 %/100%) = 43 g