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16 July, 16:59

Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm

This is a Boyle's law gas problem

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  1. 16 July, 19:43
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    P1/V1=P2/V2

    1/22.4=4/x

    X=4 multiple by 22.4

    V2=89.6L
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