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30 October, 06:40

what is the empirical formula of a compound composed of 3.25% hydrogen and 19.36% carbon and 77.39% oxygen by Mass

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  1. 30 October, 07:29
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    3.25 g H (1 H / 1.008 g H) = 3.22

    19.36 g C (1 C / 12.01 g C) = 1.61

    77.39 g O (1 O / 15.9994 g O) = 4.84

    Take the smallest number calculated and divide the others by it.

    1.61/1.61 = 1

    C = 1.

    3.22/1.61 = 2

    H = 2

    4.84/1.61 = 3

    O = 3

    =CH2O3
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