2HCI + Na, so, - 2NaCl + H, so,

How much H, so, is produced when 40.0g of HCl react?

ОА 107.60

в 36.5 g

с 08.1 g

O D53.8 g

None of the options are correct.

The correct answer is 1.10g

Explanation:

First, we'll begin by balancing the equation given above. This is illustrated below:

2HCl + 2Na - > 2NaCl + H2

Next, let us calculate the mass of HCl that reacted and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 2 x 36.5 = 73g

Molar Mass of H2 = 2x1 = 2g/mol

Now we can easily find the mass of H2 produced when 40g of HCl reacted as shown below:

From the balanced equation,

73g of HCl produced 2g of H2.

Therefore, 40g of HCl will produce = (40 x 2) / 73 = 1.10g of H2.

From the calculations made above,

40g of HCl produced 1.10g of H2