On the basis of periodic trends, choose the larger atom from each pair (if possible) : match the elements in the left column to the appropriate blanks in the sentences on the right. make certain each sentence is complete before submitting your answer.

The given question is incomplete. The complete question is as follows.

On the basis of periodic trends, choose the larger atom from each pair (if possible) : match the elements in the left column to the appropriate blanks in the sentences on the right. make certain each sentence is complete before submitting your answer.

Sn, F, Ge, not predictable, Cr

Of Ge or Po, the larger atom is ...

Of F or Se, the larger atom is ...

Of Sn or I, the larger atom is ...

Of Cr or W, the larger atom is ...

Explanation:

When we move down a group then there occurs an increase in atomic size of the atoms due to increase in the number of electrons.

Ge is a group 14 element which lies in period 4 and Po is a group 16 element that lies in period 6. As polonium is larger in size as compared to germanium.

Fluorine is a group 17 element and lies in period 2. Selenium is a group 16 element lies in 4. Therefore, selenium is larger in size as compared to fluorine.

Sn is a group 14 element that lies in period 5 and I is a group 17 element that lies in period 5. Hence, I is a larger atom.

Cr is a d-block element which lies in period 4 and W is also a d-block element which lies in period 6. Hence, W is larger in size than Cr.

Thus, we can conclude that given blanks are matched as follows.

Of Ge or Po, the larger atom is Po. Of F or Se, the larger atom is Se. Of Sn or I, the larger atom is I. Of Cr or W, the larger atom is W.