Zinc reacts with hydrochloric acid according to the reaction equation how many milliliters of 3.50 m hcl (aq) are required to react with 2.25 g of zn (s) ?

The balanced chemical reaction of Zn with HCl is

Zn + 2HCl - -> ZnCl2 + H2 (g)

So here one mole of Zn reacts with two moles of HCl

Moles of Zn = mass of Zn / atomic mass of Zn = 2.25 / 65.38 = 0.0344

so moles of HCl reacted = 2 X moles of Zn = 2 X 0.0344 = 0.0688

Moles = molarity X volume

Therefore

Volume = moles / molarity = 0.0688 / 3.50 = 0.019657 L = 19.657 mL