Given the following reaction:

3FeO + 2Cu3N - -> Fe3N2 + 3Cu2O

How many moles of copper (I) nitride are needed to form 35.7 grams of copper (I) oxide?

Question options:

.213

.166

.198

.312

(Answer) 0.166 moles of copper (I) nitride are needed.

Mass of copper (I) oxide = 35.7 g

Moles of copper (I) oxide formed by the reaction = (Mass / molar mass)

= (35.7 g / 143.09 g/mol) = 0.25 moles

According to the balanced chemical equation,

mole ratio of copper (I) nitride and copper (I) oxide = 2: 3

Therefore, moles of copper (I) nitride needed to form 0.25 moles of copper (I) oxide = (2/3 x 0.25) moles = 0.166 moles.

Thus, 0.166 moles of copper (I) nitride are needed to form 0.25 moles of copper (I) oxide.