The reaction 2a + 3b → c is first order with respect to a and

b. when the initial concentrations are [a] = 1.60 * 10-2 m and [b] = 2.67 * 10-3 m, the rate is 2.65 * 10-4 m/s. calculate the rate constant of the reaction. enter your answer in scientific notatio

6.30 M⁻¹s⁻¹.

Explanation:

As the reaction is first order with respect to a and b.

The rate of the reaction = k [a][b],

where, k is the rate constant of the reaction.

The rate of the reaction = 2.65 * 10⁻⁴ M/s,

[a] = 1.60 * 10⁻² M,

[b] = 2.67 * 10⁻³ M.

∴ k = (the rate of the reaction / [a][b]) = (2.65 * 10⁻⁴ M/s) / (1.60 * 10⁻² M) (2.67 * 10⁻³ M) = 6.30 M⁻¹s⁻¹.