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Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2, what is the limiting reactant?

FeS2

Fe2O3

O2

SO2

+2
Answers (1)
  1. Today, 10:28
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    The given reaction is:

    4FeS2 + 11O2 → 2Fe2O3 + 8SO2

    Reaction condition:

    8 moles of FeS2

    15 moles of O2

    Moles of Fe2O3 formed under the given condition can be deduced as follows:

    Based on reaction stoichiometry,

    4 moles of FeS2 forms 2 moles of Fe2O3

    Therefore, 8 moles of FeS2 would produce: 8*2/4 = 4 moles of Fe2O3

    In addition:

    11 moles of O2 forms 2 moles of Fe2O3

    Therefore, 15 moles of O2 would produce: 15 * 2/11 = 2.73 moles of Fe2O3

    Therefore, the limiting reagent is O2.
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