What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP, pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R = 0.08205 L. atm/mol. K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V = 4.20 mol (0.08205L. atm/mol. K) (273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.