Aluminum metal and chlorine gas react to from aluminum chloride 2Al (s) + 3Cl2 (g) - -> Al2Cl6 (s) How many grams of Al2Cl6 can be produced from the reaction of 2.67 mol aluminum and 3.26 mol Cl2?

290.1 grams.

Explanation:

2 Al + 3Cl2 - --> Al2Cl6

2 moles of Al react with 3 moles of Cl2 to form 1 mole of Al2Cl6

So 2.67 moles Al reacts with 3/2 * 2.67 moles Cl2 = 4 moles of chlorine. But we only have 3.26 moles of Cl2 so this will react with only part of the available Al.

3.26 reacts with 2/3 * 3.26 = 2.173 moles of aluminium.

So the number of moles of Al2Cl6 that can be produced = 2.173 * 1/2

= 1.087 moles.

= 1.087 * (2*26.98 + 6*35.45)

= 290.1 grams.