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23 November, 03:15

What is the pOH of a solution with (OH) = 1.4 x 10-13?

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  1. 23 November, 04:59
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    12.8mol/dm³

    Explanation:

    PoH=-log[OH]'

    =-log (1.4 * 10^-13)

    =13 + log5 - log7

    12.8mol/dm³
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