What are the two oxidation states of nitrogen in nh4no2?

Oxidation state of N in (NH₄) is (-3).

Oxidation state of N in (NO₂) is (+3).

Explanation:

NH₄NO₂ is dissociated according to the equation:

NH₄NO₂ → NH₄⁺ + NO₂⁻.

We can calculate the oxidation state:

NH₄⁺:

The total oxidation state of NH₄⁺ is (+1).

The oxidation state of H is known to be (+1).

∴ Oxidation state of N + 4 (oxidation state of H) = + 1.

∴ Oxidation state of N + 4 (+1) = + 1.

∴ Oxidation state of N = + 1 - 4 = - 3.

NO₂⁻:

The total oxidation state of NO₂⁻ is (-1).

The oxidation state of O is known to be (-2).

∴ Oxidation state of N + 2 (oxidation state of O) = - 1.

∴ Oxidation state of N + 2 (-2) = - 1.

∴ Oxidation state of N - 4 = - 1.

∴ Oxidation state of N = - 1 + 4 = + 3.