Arcylonitrile, c3h3n, is the starting material for the production of a synthetic fiber and can be made from propylene, c3h6, reacting with nitrogen monoxide, no, as follows: 4 c3h6 (g) + 6 no (g) → 4 c3h3n (s) + 6 h2o (l) + n2 (g) how many moles of acrylonitrile are formed when 5.0 moles of propylene reacts with 9.0 moles of nitrogen monoxide?

5 moles of C₃H₃N

Solution:

The Balance Chemical Equation is as follow,

4 C₃H₆ + 6 NO → 4 C₃H₃N + 6 H₂O + N₂

Step 1: Calculate the Limiting Reagent,

According to Balance equation,

4 moles of C₃H₆ reacts with = 6 moles of NO

So,

5 moles of C₃H₆ will react with = X moles of NO

Solving for X,

X = (5 mol * 6 mol) : 4 mol

X = 7.5 mol of NO

It means 5 mol of C₃H₆ requires 7.5 mol of NO, while we are provided with 9 mol NO which is in excess. Therefore, C₃H₆ is the limiting reagent and will control the yield of products.

Step 2: Calculate amount of C₃H₃N produced,

According to equation,

4 moles of C₃H₆ produces = 4 moles of C₃H₃N

So,

5 moles of C₃H₆ will produce = X moles of C₃H₃N

Solving for X,

X = (5 mol * 4 mol) : 4 mol

X = 5 moles of C₃H₃N