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Yesterday, 18:52

A reaction has a standard free-energy change of - 10.90 kj mol-1 (-2.605 kcal mol-1). Calculate the equilibrium constant for the reaction at 25 °c.

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  1. Yesterday, 21:22
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    The relation between free energy change and equilibrium constant is

    ΔG = - RT ln Keq

    T = 298 K

    R = 8.314 J / mol K

    Keq = ?

    ΔG = - 10.90 kJ / mole

    ΔG = - 8.314 X 298 X ln Keq

    ln Keq = 10900 / 8.314 X 298 = 4.4

    Keq = 81.45
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