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31 January, 09:49

A sample of ideal gas is in a sealed container. The pressure of the gas is 485 torr, and the temperature is 40 ∘C. If the temperature changes to 74 ∘C with no change in volume or amount of gas, what is the new pressure, P2, of the gas inside the container?

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  1. 31 January, 10:59
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    537.68 torr.

    Explanation:

    We can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L.

    n is the no. of moles of the gas in mol.

    R is the general gas constant,

    T is the temperature of the gas in K.

    If n and V are constant, and have different values of P and T:

    (P₁T₂) = (P₂T₁).

    P₁ = 485 torr, T₁ = 40°C + 273 = 313 K,

    P₂ = ? torr, T₂ = 74°C + 273 = 347 K.

    ∴ P₂ = (P₁T₂) / (P₁) = (485 torr) (347 K) / (313 K) = 537.68 torr.
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