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7 November, 10:15

What is the volume, in l, of 0.682 moles of o'what 2 gas having a temperature of 68.2 ºc and pressure of 5.82 atm?

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  1. 7 November, 11:24
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    We will use Ideal gas equation. PV=nRT where P = pressure (in atm) = 5.82atm V=Volume=? n = moles of gases=0.682 R = gas constant = 0.0821L atm / mol K T = temperature = 68.2 C = 68.2 + 273.15 = 341.35 K V = nRT / P = 0.682 X 0.0821 X 341.35 / 5.82 V = 3.284 L.
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