If 0.89 mol of O2 has a volume of 25.0 L at a constant temperature and pressure, what would be the volume of 1.455 mol of O2?

new volume = 40.87L

Explanation:

Assume that given gas follow the ideality nature of gas

now we can use ideal gas equation:

n1=0.89mol

V1=25L

n2=1.455mol

V2=?

V1/n1=V2/n2;

After putting all the value we get,

V2=40.87L

new volume = 40.87L