In glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free-energy change (delta g'°) of 23.8 kj/mol. under what conditions encountered in a normal cell will the free-energy change (delta g) be negative, enabling the reaction to proceed spontaneously to the right?

Question

Chemistry

Ben Ayers

5 January, 15:20

In glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free-energy change (delta g'°) of 23.8 kj/mol. under what conditions encountered in a normal cell will the free-energy change (delta g) be negative, enabling the reaction to proceed spontaneously to the right?

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Camryn Spencer · Answer 1

Answer;

When there is a high concentration of fructose-1,6-bisphosphate relative to the concentration of products.

Explanation; Fructose-1,6-bisphosphate is formed at the first irreversible reaction unique to glycolytic pathway, the commited step, after the phosphorylation of fructose 6-phosphate. The reaction is catalyzed by the enzyme phosphofructokinase, and it is the primary control site in glycolysis. When there is a high concentration of fructose-1,6-bisphosphate relative to the concentration of products, the change in the free-energy will be negative, and this enables the reaction to proceed towards the formation of products from fructose-1,6-bisphosphate.