How much heat does it take to boil 10 grams of water? Assume that the water is at its boiling temperature. Heat of vaporization for water is 2261 J/g

The heat needed to boil 10 grams of water is 22,610 J

Explanation:

Heat absorbed or released in a phase change is understood as the energy supplied or extracted from the substance that is used to change the state of aggregation of matter. This heat is called latent heat.

Then, Latent Heat (L) or heat of change of state, is the energy absorbed or transferred per unit mass of substance when changing state.

The amount of heat absorbed or released by a quantity m of substance to change phase is given by:

Q=m*L

In this case:

m = 10 g L = 2261 J/g

Replacing:

Q = 10 g*2261 J/g

Solving:

Q = 22,610 J

The heat needed to boil 10 grams of water is 22,610 J