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22 August, 09:01

A 40 g sample of water at an inital temperature of 40°C is heated to 99°C. How much heat did the water absorb? The specific heat of water is 4.18J/gºC

a. 413.82j

b.-9864j

c. 9864.8j

d.-413.82j

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Answers (1)
  1. 22 August, 09:09
    0
    C.

    Explanation:

    Q = mcΔt°

    Q = 40g * 4.18 J/g*°C * (99°C - 40°C) = 9864.8 J
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